H=-16t^2+80t+3264

Solution for H=-16t^2+80t+3264 equation:

=-16H^2+80H+3264

We move all terms to the left:

-(-16H^2+80H+3264)=0

We get rid of parentheses

16H^2-80H-3264=0

a = 16; b = -80; c = -3264;
Δ = b2-4ac
Δ = -802-4·16·(-3264)
Δ = 215296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{215296}=464$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-464}{2*16}=\frac{-384}{32}
=-12
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+464}{2*16}=\frac{544}{32}
=17
$